3[7x-2(x-4)]+1=10

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Solution for 3[7x-2(x-4)]+1=10 equation:


Simplifying
3[7x + -2(x + -4)] + 1 = 10

Reorder the terms:
3[7x + -2(-4 + x)] + 1 = 10
3[7x + (-4 * -2 + x * -2)] + 1 = 10
3[7x + (8 + -2x)] + 1 = 10

Reorder the terms:
3[8 + 7x + -2x] + 1 = 10

Combine like terms: 7x + -2x = 5x
3[8 + 5x] + 1 = 10
[8 * 3 + 5x * 3] + 1 = 10
[24 + 15x] + 1 = 10

Reorder the terms:
24 + 1 + 15x = 10

Combine like terms: 24 + 1 = 25
25 + 15x = 10

Solving
25 + 15x = 10

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-25' to each side of the equation.
25 + -25 + 15x = 10 + -25

Combine like terms: 25 + -25 = 0
0 + 15x = 10 + -25
15x = 10 + -25

Combine like terms: 10 + -25 = -15
15x = -15

Divide each side by '15'.
x = -1

Simplifying
x = -1

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